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# C program to calculate the sum of series 1 +1/x^1 + 1/x^2 + 1/x^3 ... + 1/x^n terms

Here, we are going to implement a **c program that will find the sum of series 1 +1/x^1 + 1/x^2 + 1/x^3 ... + 1/x^n terms**.

Submitted by **IncludeHelp**, on March 04, 2018

## Program to calculate sum of series 1 +1/x^1 + 1/x^2 + 1/x^3 ... + 1/x^n terms in C

#include <stdio.h>
#include <math.h>
int main()
{
int x,n,i;
float sum=0;
printf("Enter total number of terms: ");
scanf("%d",&n);
printf("Enter the value of x: ");
scanf("%d",&x);
for(i=1; i<=n; i++){
sum += 1+(1/pow(x,i));
}
printf("Sum of the series: %f\n",sum);
return 0;
}

**Output**

Enter total number of terms: 5
Enter the value of x: 2
Sum of the series: 5.968750

**Solution**

**Series is:**
1+1/x^1 + 1/x^2+ 1/x^3 ... + 1/x^n
**Here,**
x=2
n=5
1+1/2^1 + 1+1/2^2 + 1+1/2^3 + 1+1/2^4 + 1+1/2^5
1+1/2 + 1+1/4 + + 1+1/8 + 1+1/16 + 1+1/32
1+0.5 + 1+0.25 + 1+0.125 + 1+0.0625 + 1+0.03125
= **5.968750**

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