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# Java program to find sum of factorials from 1 to N

Here, we are implementing a java program that will read the value of N and **find sum of the factorials from 1 to N**. It is a **solution of series 1! + 2! + 3! + 4! + ... N! in java.**

Submitted by **Chandra Shekhar**, on January 06, 2018

**Given N and we have find the solution of series 1! + 2! + 3! + 4! + ... N! using Java program. (Sum of the factorials from 1 to N).**

**Example:**

Input: 3
Output: 9
Explanation:
1! + 2! + 3! = 1 + 2 + 6 = 9
Input: 5
Output: 152
Explanation:
1! + 2! + 3! + 4! + 5!
= 1+2+6+24+120
= 153

## Find sum of the factorials using java program

import java.util.Scanner;
public class SumOfFactorial
{
public static void main(String[] args)
{
// create scanner class object.
Scanner sc = new Scanner(System.in);
// enter the number.
System.out.print("Enter number : ");
int n = sc.nextInt();
int total=0;
int i=1;
// calculate factorial here.
while(i <= n)
{
int factorial=1;
int j=1;
while(j <= i)
{
factorial=factorial*j;
j = j+1;
}
// calculate sum of factorial of the number.
total = total + factorial;
i=i+1;
}
// print the result here.
System.out.println("Sum : " + total);
}
}

**Output**

First run:
Enter number : 3
Sum : 9
Second run:
Enter number : 5
Sum : 153

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