Swift program to convert an optional string into the normal string

Here, we are going to learn how to convert an optional string into the normal string in Swift programming language?
Submitted by Nidhi, on June 10, 2021

Problem Solution:

Here, we will read a string from user using readLine() function and the readLine() function returns optional string. Then we will convert the optional string into the normal string using the "!" operator. After that, we will print the result on the console screen.

Program/Source Code:

The source code to convert the optional string into the normal string is given below. The given program is compiled and executed successfully.

// Swift program to convert an optional string 
// into the normal string

import Swift;

var str:String="";

print("Enter String:");
str = readLine()!;

print("String is: ",str);

Output:

Enter String:
Hello World
String is:  Hello World

...Program finished with exit code 0
Press ENTER to exit console.

Explanation:

In the above program, we imported a package Swift to use the print() function using the below statement,

import Swift;

Here, we read a string using the readLine() function. The readLine() function returns optional string. Then we converted the optional string into a normal string using the "!" operator. After that, we printed the result on the console screen.

Swift String Programs »





Comments and Discussions!

Load comments ↻





Copyright © 2024 www.includehelp.com. All rights reserved.