# C++ program to print all Even and Odd numbers from 1 to N

Here, we are going to learn how to create a C++ program to print all Even and Odd numbers from 1 to N?
Submitted by IncludeHelp, on December 22, 2019

Problem: Take input from the user (N) and print all EVEN and ODD numbers between 1 to N.

Solution:

• Input an integer number (N).
• Run two separate loops from 1 to N.
• In the first loop, check the condition to check EVEN numbers and print them.
• In the second loop, check the condition to check ODD numbers and print them.
• To check EVEN/ODD number – find the remainder dividing by 2, if it is 0 then the number will be an EVEN number, else the number will be an ODD number.

C++ program:

```// C++ program to print all
// Even and Odd numbers from 1 to N

#include <iostream>
using namespace std;

// function : evenNumbers
// description: to print EVEN numbers only.
void evenNumbers(int n)
{
int i;
for (i = 1; i <= n; i++) {
//condition to check EVEN numbers
if (i % 2 == 0)
cout << i << " ";
}
cout << "\n";
}

// function : oddNumbers
// description: to print ODD numbers only.
void oddNumbers(int n)
{
int i;
for (i = 1; i <= n; i++) {
//condition to check ODD numbers
if (i % 2 != 0)
cout << i << " ";
}
cout << "\n";
}

// main code
int main()
{
int N;
// input the value of N
cout << "Enter the value of N (limit): ";
cin >> N;

cout << "EVEN numbers are...\n";
evenNumbers(N);

cout << "ODD numbers are...\n";
oddNumbers(N);

return 0;
}
```

Output

```RUN 1:
Enter the value of N (limit): 11
EVEN numbers are...
2 4 6 8 10
ODD numbers are...
1 3 5 7 9 11

RUN 2:
Enter the value of N (limit): 50
EVEN numbers are...
2 4 6 8 10 12 14 16 18 20 22 24 26 28 30 32 34 36 38 40 42 44 46 48 50
ODD numbers are...
1 3 5 7 9 11 13 15 17 19 21 23 25 27 29 31 33 35 37 39 41 43 45 47 49
```