# Python | Count total number of bits in a number

Count total number of bits in a number in Python: A number is given and we have to find its total number of bits to be stored using Python program.
Submitted by IncludeHelp, on September 05, 2018

Prerequisite: Binary number systems in Python

Given a number and we have to find total number of bits of binary value to represent the number using Python.

Example:

```    Input:
num = 61
Binary value of 61 is = 0b111101
Output:
Total number of bits = 6
Note: '0b' is prefixed to represent binary value

Input:
num = 12
Binary value of 61 is = 0b1100
Output:
Total number of bits = 4
```

Program:

```# count total number of bits in a number

# declare a number
num = 61

# use bin () method to get the binary value of a number
# print binary value output will be 0b111101
print "binary value of {0} is: {1}".format (num, bin(num))

# store the length of the binary number
length = len(bin(num))

# since binary value contains 0b as prefix
# so to get exact length total number of bits
# subtract 2 from the length
length -=2

# print length
print "total number of bits: ", length
```

Output

```binary value of 61 is: 0b111101
total number of bits:  6
```

### By defining function

In the below program, we used len(bin(n)[2:]), it will return total length of the binary value after 2 characters.

Let’s understand

```    a=61
= len(bin(a)[2:])		# bin(a) is '0b111101'
= len('0b111101'[2:])
= len ('111101')
= 6
```

Program:

```# count total number of bits in a number
# function to get total bits
def totalBits(n):
return len(bin(n)[2: ])

#main code
a = 61
b = 12

print "Total bits in {0} = {1} ".format(a,totalBits(a))
print "Total bits in {0} = {1} ".format(b,totalBits(b))
```

Output

```Total bits in 61 = 6
Total bits in 12 = 4
```

Preparation