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Python program for Find sum of odd factors of a number
By IncludeHelp Last updated : February 17, 2024
Problem statement
Given an integer number, write a Python program to find the sum of odd factors of the given number.
Consider the below example with sample values:
Input:
num = 120
Odd factors of 120 are: 1, 3, 5, 15
Output:
Sum of all odd factors is: 1 + 3 + 5 + 15 = 24
Input:
num = 55
Odd factors of 55are: 1, 5, 11, 55
Output:
Sum of all odd factors is: 1 + 5 + 11 + 55 = 24
Finding of sum of odd factors of a number
To find the sum of odd factors, find the factors of a number and ignore the even factors with their powers. To remove all even factors, divide the given number if it is divisible by 2 repeatedly and use another loop to get and find the sum of odd factors.
# Import math module
import math
# Function that returns the sum of odd factors
# of the given number
def SumOddFactors(num):
# Traversing through all
# prime factors.
result = 1
# Ignoring even factors
while num % 2 == 0:
num = num // 2
for i in range(3, int(math.sqrt(num) + 1)):
count = 0
curr_sum = 1
curr_term = 1
while num % i == 0:
count += 1
num = num // i
curr_term *= i
curr_sum += curr_term
result *= curr_sum
# For prime number
if num >= 2:
result *= 1 + num
return result
# The main code
num = 120
print(SumOddFactors(num))
num = 55
print(SumOddFactors(num))
Output
The output of the above code is:
24
72
To understand the above program, you should have the basic knowledge of the following Python topics:
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