Python | Print all numbers between 1 to 1000 which are divisible by 7 and must not be divisible by 5

Here, we are going to implement a Python program that will print all numbers between 1 to 1000, which are divisible by 7 and must not be divisible by 5.
Submitted by IncludeHelp, on August 09, 2018

Given a range (which is 1 to 1000) and we have print all numbers which are divisible bye 7 and not divisible by 5 in python.

Example:

```    Input:
Given input range is 1 to 1000

Output:
7, 14, 21, 28, 42, 49, 56, ...
```

Logic:

• To implement this logic, we will use a for and in loop with range() method. The statement of range() method with the minimum to maximum range is range(begin, end+1).
• And, check the condition, that value should be divisible by 7 and should not be divisible by 5 (example code: ((cnt%7==0) and (cnt%5!=0)) ).
• If condition is true, print the numbers.

Program:

```# define range in variables
# so that we can change them anytime
begin 	= 1
end 	= 1000

# loop to check and print the numbers
# which are divisible by 7 and not
# divisible by 5
for cnt in range(begin, end+1):
if( cnt%7==0 and cnt%5!=0 ):
print cnt, # command after cnt will print space
```

Output

```    7 14 21 28 42 49 56 63 77 84 91 98 112 119 126
133 147 154 161 168 182 189 196 203 217 224 231
238 252 259 266 273 287 294 301 308 322 329 336
343 357 364 371 378 392 399 406 413 427 434 441
448 462 469 476 483 497 504 511 518 532 539 546
553 567 574 581 588 602 609 616 623 637 644 651
658 672 679 686 693 707 714 721 728 742 749 756
763 777 784 791 798 812 819 826 833 847 854 861
868 882 889 896 903 917 924 931 938 952 959 966
973 987 994
```

Preparation