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Ruby program to cyclically permutes the elements of the array

Last Updated : December 15, 2025

Problem Solution

In this program, we will create an array of integers and then we will cyclically permute the elements of the array and print the result.

Program/Source Code

The source code to cyclically permute the elements of the array is given below. The given program is compiled and executed successfully.

# Ruby program to Cyclically Permute the 
# elements of array

arr = [12,69,49,87,68];

print "Array elements before Cyclically Permutation: \n";
i=0;
while(i<5)
    print arr[i]," ";
    i=i+1;
end

i=0;
t = arr[0];
while(i<5)
    if(i==4)
        arr[i]=t;
    else
        arr[i]=arr[i + 1];
    end
    i = i + 1;
end
        
print "\nArray elements after Cyclically Permutation: \n";
i=0;
while(i<5)
    print arr[i]," ";
    i=i+1;
end

Output

Array elements before Cyclically Permutation: 
12 69 49 87 68 
Array elements after Cyclically Permutation: 
69 49 87 68 12 

Explanation

In the above program, we created an array of integer elements. Then we cyclically permutated the elements of the array. After that, we printed the result.

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