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Scala program to print the elements of a sequence except first element using tail property

Here, we are going to learn how to print the elements of a sequence except first element using tail property in Scala programming language?
Submitted by Nidhi, on June 03, 2021

Problem Solution:

Here, we will create a sequence of integer numbers using Seq collection class. Then we will get the elements of a sequence except the first element using the tail property and print the result on the console screen.

The Seq is a trait. It is used to represent the indexed sequence. It is immutable. It also maintains the insertion order of elements.

Program/Source Code:

The source code to print the elements of a sequence except the first element using the tail property is given below. The given program is compiled and executed on the ubuntu 18.04 operating system successfully.

// Scala program to print the elements of a sequence except
// the first element using the tail property

import scala.collection.immutable._

object Sample {
  // Main method
  def main(args: Array[String]) {
    var nums: Seq[Int] = Seq(10, 20, 30, 20, 56, 67, 78);

    println("Element of sequence except first element: ");
    println(nums.tail);
  }
}

Output:

Element of sequence except first element: 
List(20, 30, 20, 56, 67, 78)

Explanation:

Here, we used an object-oriented approach to create the program. And, we imported Collection classes using below statement,

import scala.collection.immutable._

Here, we also created a singleton object Sample and defined the main() function. The main() function is the entry point for the program.

In the main() function, we created a sequence nums using Seq collection. Then we got the elements of created sequence except the first element using the tail property and printed the result on the console screen.

Scala Sequence Programs »

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