C# program to calculate the VARIANCE of a set of given numbers

Here, we are going to learn how to calculate the VARIANCE of a set of given numbers in C#?
Submitted by Nidhi, on September 21, 2020

Here we will calculate the VARIANCE of a set of given numbers and then print the calculated VARIANCE on the console screen.

Program:

The source code to calculate the VARIANCE of a set of given numbers is given below. The given program is compiled and executed successfully on Microsoft Visual Studio.

//C# Program to Find the VARIANCE of a set of given numbers.

using System;
using System.Collections.Generic;

class Program
{
    private static void Main()
    {
        List<double> list = new List<double> { 1, 2, 3, 4, 5, 6};
 
        double mean     = 0;
        double variance = 0;
        double sum      = 0;

        double temp = 0;
        int loop = 0;

        for (loop = 0; loop < list.Count; loop++)
        {
            sum += list[loop];
        }

        mean = sum / (list.Count - 0);


        for (loop = 0; loop < list.Count; loop++)
        {
            temp += Math.Pow((list[loop] - mean), 2);
        }
        variance=temp / (list.Count - 0);


        Console.WriteLine("Mean    : " + mean    );
        Console.WriteLine("Variance: " + variance);
    }
}

Output:

Mean    : 3.5
Variance: 2.91666666666667
Press any key to continue . . .

Explanation:

Here, we created a class Demo that contains a static method Main(). The Main() method is the entry point of the program. Here we created the list of numbers, and then calculate the MEAN, VARIANCE of the given list of numbers. After that, we printed the calculated values on the console screen.






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