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C# program to demonstrate example of nested if else statement
C# nested if else statement example: Here, we are writing a C# program to demonstrate example of nested if else statement.
Submitted by IncludeHelp, on April 07, 2019
Like other programming languages, in C# also conditions may be checked within a condition, i.e. nested if-else allows us to check other conditions within if or else block.
Syntax:
if(test_condition1){
//code section 1
if(test_condition_a){
//code section a
}
else{
//code section b
}
}
else if(test_condition2){
{
//code section 2
}
else if(test_condition3){
//code section 3
}
...
else{
//else code section
}
See the syntax above, here we are checking test_condition_a within the test_conditon1 block, if test_condition1 will be true, "code section a" will be executed.
C# example for nested if else statement
Here, we are asking for a character – and check whether it is vowel or consonant, if input character is a valid alphabet
// C# program to demonstrate example of
// nested if else statement
using System;
using System.IO;
using System.Text;
namespace IncludeHelp
{
class Test
{
// Main Method
static void Main(string[] args)
{
//input a character and check whether it is vowel or consonant
//but before it - check input character is an aplhabet or not
char ch;
Console.Write("Enter a character: ");
ch = Console.ReadLine()[0];
//check ch is an alphabet or not
if((ch>='A' && ch<='Z') || (ch>='a' && ch<='z')){
Console.WriteLine("{0} is a valid alphabet", ch);
//checking for vowel or consonant
if (ch == 'A' || ch == 'a' || ch == 'E' || ch == 'e' ||
ch == 'I' || ch == 'i' || ch == 'O' || ch == 'o' ||
ch == 'U' || ch == 'u')
{
Console.WriteLine("{0} is a vowel", ch);
}
else
{
Console.WriteLine("{0} is a consonant", ch);
}
}
else{
Console.WriteLine("{0} is not a valid alphabet",ch);
}
//hit ENTER to exit the program
Console.ReadLine();
}
}
}
Output
First run:
Enter a character: X
X is a valid alphabet
X is a consonant
Second run:
Enter a character: u
u is a valid alphabet
u is a vowel
Third run:
Enter a character: $
$ is not a valid alphabet
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