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Python program to extract and print digits in reverse order of a number

Extracting digits in Python: Here, we are going to learn how to extract and print the digits in reverse order of a number in Python?
Submitted by Anuj Singh, on June 04, 2019

Here, we are going to use some mathematical base while programming. The problem is, when you ask a number from the user, the user would give input as multiple digit number (considering integer only). So it is easy to find the type of number but it’s not easy to find the number of digits in the number.

So, in the following problem, we are going to use the mathematical trick of:

1. Subtracting the remainder after dividing it by 10 i.e. eliminating the last digit.
2. Dividing an integer by 10 gives up an integer in computer programming (the above statement is only true when the variables are initialized as int only).

Example:

    Input: 12345

    Output: 54321

Python code to extract and print digits of a number in reverse order

num = int(input("Enter a number with multiple digit: "))
n=0
while num>0:
    a = num%10
    num = num - a
    num = num/10
    print(int(a),end="")
    n = n + 1   
print(n)

Output

Enter a number with multiple digit: 123456789
9876543219

Here, we are first using a loop with condition num>0, and the last digit of the number is taken out by using simple % operator after that, the remainder term is subtracted from the num. Then number num is reduced to its 1/10^th so that the last digit can be truncated.

The cycle repeats and prints the reverse of the number num.

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