# Remove all occurrences of an element from a Python list

Removing all occurrences of a list element: In this tutorial, we will learn how to remove all occurrences of a given element in the Python list. Learn with logic and examples. By IncludeHelp Last updated : August 17, 2023

## Problem statement

Given a Python list, we have to remove all occurrences of the given elements from it.

## Remove all occurrences of a given element

Removing an element can be done using the list.remove() method. But when you want to remove all occurrences of a given element, you need to iterate over the list elements and remove all occurrences of that element by using the list.remove() method.

### Example

Consider the below example without sample input and output:

```Input:
list = [10, 20, 10, 30, 10, 40, 10, 50]
n = 10

Output:
list after removing 10 from the list
list = [20, 30, 40, 50]
```

## Method 1: Iterating over the list using for ... in and remove() method

### Logic

• Declare a list and initialize it with elements.
• Declare a number (n) to be deleted from the list.
• Iterate over the list using the for … in loop.
• Check each element whether it is equal to the number (n). If the condition is True then remove the element using the remove() method.

### Program

```# list with integer elements
list = [10, 20, 10, 30, 10, 40, 10, 50]
# number (n) to be removed
n = 10

# print original list
print ("Original list:")
print (list)

# loop to traverse each element in list
# and, remove elements
# which are equals to n
for x in list:
if x == n:
list.remove(x)

# print list after removing given element
print ("list after removing elements:")
print (list)
```

Output

```Original list:
[10, 20, 10, 30, 10, 40, 10, 50]
list after removing elements:
[20, 30, 40, 50]
```

## Method 2: Iterating over the list using while loop and remove() method

### Logic

• Run a while loop from 0th element to last element's index.
• Check the element whether it is equal to the number (which is to be removed) or not.
• If any element of the list is equal to the number (which is to be removed), remove that element from the list.
• To remove the number from the list, use list.remove() method.
• After removing the number/element from the list, decrease the length, because one item is deleted, and then continue the loop to check the next item at same index (because after removing the element – next elements shifts to the previous index.
• If element is not found (i.e. is not removed), then increase the loop counter to check next element.

### Program

```# list with integer elements
list = [10, 20, 10, 30, 10, 40, 10, 50]

# number (n) to be removed
n = 10

# print original list
print("Original list:")
print(list)

# loop to traverse each element in list
# and, remove elements
# which are equals to n
i = 0  # loop counter
length = len(list)  # list length
while i < length:
if list[i] == n:
list.remove(list[i])
# as an element is removed
# so decrease the length by 1
length = length - 1
# run loop again to check element
# at same index, when item removed
# next item will shift to the left
continue
i = i + 1

# print list after removing given element
print("list after removing elements:")
print(list)
```

Output

```Original list:
[10, 20, 10, 30, 10, 40, 10, 50]
list after removing elements:
[20, 30, 40, 50]
```