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Scala program to handle multiple exceptions

Here, we are going to learn how to handle multiple exceptions in Scala programming language?
Submitted by Nidhi, on June 07, 2021

Problem Solution:

Here, we will create a program to handle multiple exceptions. And, we will use try and catch blocks. The source code written inside the try block may generate an exception. Then we handle generated exceptions in the catch block.

To handle the Throwable keyword to handle the unknown exception.

Program/Source Code:

The source code to handle multiple exceptions is given below. The given program is compiled and executed on the ubuntu 18.04 operating system successfully.

// Scala program to handle multiple exceptions

object Sample {
  // Main method
  def main(args: Array[String]) {
    var num1: Int = 2;
    var num2: Int = 10;
    var res: Int = 0;
    var arr = Array(1, 2, 3, 4, 5);

    try {
      res = num2 / num1;

      println("Result: " + res);
      println(arr(6));
    } catch {
      case a: ArithmeticException =>
        println("Divide By Zero Exception occurred.");
      case e: Throwable => println("Unknown Exception");
    }
  }
}

Output:

Result: 5
Unknown Exception

Explanation:

In the above program, we used an object-oriented approach to create the program. And, we created a singleton object Sample and defined the main() function. The main() function is the entry point for the program.

In the main() function, we created three integer variables num1, num2, res, that are initialized with 2, 10, 0 respectively.

And, we created an array of integers with 5 elements. But we used index 6 in the array. That will generate an exception and then we printed the message on the console screen.

Scala Exception Handling Programs »


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