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VB.Net program to demonstrate the CInt() function

Here, we are going to demonstrate the CInt() function in VB.Net.
Submitted by Nidhi, on December 04, 2020 [Last updated : March 05, 2023]

CInt() function in VB.Net

The CInt() function is used to convert different data types value into the integer type.

Syntax

CInt(val)

Parameter(s)

• val: It may be a variable of different data types.

Return Value

The CInt() function will return a converted integer number.

VB.Net code to demonstrate the example of CInt() function

The source code to demonstrate the CInt() function is given below. The given program is compiled and executed successfully.

'VB.Net program to demonstrate the CInt() function.

Module Module1

    Sub Main()
        Dim num As Integer = 0

        Dim n1 As Double = 10.25
        Dim n2 As Single = 12.25
        Dim n3 As Byte = 25
        Dim n4 As String = "223"

        num = CInt(n1)
        Console.WriteLine("Integer Number: {0}", num)

        num = CInt(n2)
        Console.WriteLine("Integer Number: {0}", num)

        num = CInt(n3)
        Console.WriteLine("Integer Number: {0}", num)

        num = CInt(n4)
        Console.WriteLine("Integer Number: {0}", num)
    End Sub
    
End Module

Output:

Integer Number: 10
Integer Number: 12
Integer Number: 25
Integer Number: 223
Press any key to continue . . .

Explanation:

In the above program, we created a module Module1 that contains a Main() method. In the Main() method, we created five variables num, n1, n2, n3, and n4 those are initialized with 0, 10.25, 12.25, 25, and "223".

num = CInt(n1)
Console.WriteLine("Integer Number: {0}", num)

num = CInt(n2)
Console.WriteLine("Integer Number: {0}", num)

num = CInt(n3)
Console.WriteLine("Integer Number: {0}", num)

num = CInt(n4)
Console.WriteLine("Integer Number: {0}", num)

Here, we converted the value of the specified variable into integer and printed them on the console screen.

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