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Java - Long Class highestOneBit() Method

Long class highestOneBit() method: Here, we are going to learn about the highestOneBit() method of Long class with its syntax and example. By Preeti Jain Last updated : March 20, 2024

Long class highestOneBit() method

• highestOneBit() method is available in java.lang package.
• highestOneBit() method is used to find at most only single 1's bit from the leftmost side one bit in the path of the highest order of the given parameter [value] of long type.
• highestOneBit() method is a static method, it is accessible with the class name too and if we try to access the method with the class object then also we will not get an error.
• highestOneBit() method does not throw an exception at the time of determining the highest order bit in a single digit.

Syntax

    public static long highestOneBit (long value);

Parameters

• long value – represents the long value to be parsed.

Return Value

The return type of this method is long, it returns the long value based on the following cases,

• If the given argument is non-zero then, it returns at most only single 1's bit in the path of leftmost side one bit of the given long value.
• Else, if the given argument is zero then, it returns the value 0.

Example

// Java program to demonstrate the example 
// of highestOneBit (long value) method of Long class

public class HighestOneBitOfLongClass {
    public static void main(String[] args) {
        long value = 1296;

        // It returns the string representation of the given unsigned 
        // long value denoted by the argument in binary by calling
        // Long.toBinaryString(value)
        System.out.println("Long.toBinaryString(value): " + Long.toBinaryString(value));

        // It returns the number with atmost 1's bits in the path of leftmost side 
        // one bit in the given argument 'value' by calling Long.highestOneBit(value)
        System.out.println("Long.highestOneBit(value): " + Long.highestOneBit(value));
    }
}

Output

Long.toBinaryString(value): 10100010000
Long.highestOneBit(value): 1024