# Java Math Class static double log10(double d) with example

Java Math Class static double log10(double d) method: Here, we are going to learn about the static double log10(double d) method of Math Class with its syntax and example.
Submitted by Preeti Jain, on September 04, 2019

## Math Class static double log10(double d)

• This method is available in java.lang package.
• This method is used to return the logarithm of the given (base 10) of the given argument in the method.
• This is a static method so it is accessible with the class name too.
• The return type of this method is double, it returns the logarithm (base 10) of the given argument.
• In this method, we pass only one parameter as the double type whose logarithm (base 10) to be found.
• This method does not throw any exception.

Syntax:

```    public static double log10(double d){
}
```

Parameter(s): It accepts a double value, whose logarithm (base 10) to be found.

Return value:

The return type of this method is double, it returns the logarithm (base 10) of the given argument.

Note:

• If we pass "NaN", it returns "NaN".
• If we pass an argument which is equal to 10*n (n should be an integer type), it returns the n.
• If we pass a positive infinity, it returns the same (positive infinity).
• If we pass zero (-0 or 0), it returns the negative infinity.

### Java program to demonstrate example of log10(double d) method

```// Java program to demonstrate the example of
// log10(double d) method of Math Class

public class Log10Method {
public static void main(String[] args) {
// Here we are declaring few variables
double d1 = 7.0 / 0.0;
double d2 = -0.0;
double d3 = 6054.2;

// displaying values
System.out.println("d1: " + d1);
System.out.println("d2: " + d2);
System.out.println("d3: " + d3);

// Here , we will get (Infinity) because we are
// passing parameter whose value is (-infinity)
System.out.println("Math.log10(d1): " + Math.log10(d1));

// Here , we will get (-Infinity) because we are
// passing parameter whose value is (-0.0)
System.out.println("Math.log10(d2): " + Math.log10(d2));

// Here , we will get (log [10 raised to the power of
// the given argument]) and we are passing parameter
// whose value is (6054.2)
System.out.println("Math.log10(d1): " + Math.log10(d3));
}
}
```

Output

```E:\Programs>javac Log10Method.java

E:\Programs>java Log10Method
d1: Infinity
d2: -0.0
d3: 6054.2
Math.log10(d1): Infinity
Math.log10(d2): -Infinity
Math.log10(d1): 3.782056763740091
```

Languages: » C » C++ » C++ STL » Java » Data Structure » C#.Net » Android » Kotlin » SQL
Web Technologies: » PHP » Python » JavaScript » CSS » Ajax » Node.js » Web programming/HTML
Solved programs: » C » C++ » DS » Java » C#
Aptitude que. & ans.: » C » C++ » Java » DBMS
Interview que. & ans.: » C » Embedded C » Java » SEO » HR
CS Subjects: » CS Basics » O.S. » Networks » DBMS » Embedded Systems » Cloud Computing
» Machine learning » CS Organizations » Linux » DOS
More: » Articles » Puzzles » News/Updates