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Java StrictMath IEEEremainder() method with example

StrictMath Class IEEEremainder() method: Here, we are going to learn about the IEEEremainder() method of StrictMath Class with its syntax and example.
Submitted by Preeti Jain, on December 26, 2019

StrictMath Class IEEEremainder() method

• IEEEremainder() method is available in java.lang package.
• IEEEremainder() method is used to return the calculated remainder on the given two parameters.
• IEEEremainder() method is followed by IEEE 754 Standard.
• IEEEremainder() method is a static method so it is accessible with the class name and if we try to access the method with the class object then we will not get an error.
• As we all know that when we calculate the remainder so for that we need two numbers (one is dividend and other is divisor) and it also returns two numbers ( one is the quotient and other is remainder).
• Let suppose if the dividend is fully divisible by divisor then the value of remainder will be 0 and in that case, the resultant value sign will be the same as the sign of the first argument.
• IEEEremainder() method does not throw any exception.

Syntax:

    public static double IEEEremainder(double divi, double divisor);

Parameter(s):

• double divi, double divisor – First argument represents the dividend and the second argument represents the divisor.

Return value:

The return type of this method is double – it returns the remainder of the given arguments.

Note:

• If we pass infinity in any of the arguments, method returns the NaN.
• If we pass NaN in any of the arguments, method returns NaN.
• If we pass 0 (negative or positive), method returns NaN.
• If we pass a finite value as the first argument and an infinite value as the second argument, method returns the first argument.

Example:

// Java program to demonstrate the example of 
// IEEEremainder(double divi, double divisor) 
// method of StrictMath class.

public class IEEEremainder {
    public static void main(String[] args) {
        // variable declarations
        Double d1 = 7.0 / 0.0;
        Double d2 = 10.0;
        Double d3 = 5.0;
        Double d4 = 0.0;
        Double d5 = -0.0;

        // Display previous value of d1,d2,d3,d4 andd5  
        System.out.println("d1: " + d1);
        System.out.println("d2: " + d2);
        System.out.println("d3: " + d3);
        System.out.println("d4: " + d4);
        System.out.println("d5: " + d5);

        // Here , we will get (NaN) because we are 
        // passing first parameter whose value is (infinity)
        System.out.println("StrictMath. IEEEremainder (d1,d2): " + StrictMath.IEEEremainder(d1, d2));

        // Here , we will get (NaN) because we are passing 
        // second parameter whose value is (positive or negative 0)
        System.out.println("StrictMath. IEEEremainder (d2,d4): " + StrictMath.IEEEremainder(d2, d4));

        // Here , we will get (first argument) because we are 
        // passing finite parameter  as first argument whose value is (10.0) 
        // and passing infinity as second argument in the method.
        System.out.println("StrictMath. IEEEremainder (d2,d1): " + StrictMath.IEEEremainder(d2, d1));

        // Here , we will get (0.0) because we are passing 
        // parameter whose value is (10.0,5.0)
        System.out.println("StrictMath. IEEEremainder (d2,d3): " + StrictMath.IEEEremainder(d2, d3));
    }
}

Output

d1: Infinity
d2: 10.0
d3: 5.0
d4: 0.0
d5: -0.0
StrictMath. IEEEremainder (d1,d2): NaN
StrictMath. IEEEremainder (d2,d4): NaN
StrictMath. IEEEremainder (d2,d1): 10.0
StrictMath. IEEEremainder (d2,d3): 0.0