# Rust program to calculate the power of a given number

Input the number (n) and power (p), find the power of the given number i.e., n to the power p (np) using Rust program.
Submitted by Nidhi, on September 26, 2021

Problem Solution:

Here, we will read the number and power from the user. Then we will calculate the power of a given number using the pow() function and print the result.

Program/Source Code:

The source code to calculate the power of a given number is given below. The given program is compiled and executed successfully.

```// Rust program to calculate the
// power of given number

use std::io;

fn main() {
let mut n:u32 = 0;
let mut p:u32 = 0;
let mut res:u32 = 0;

let mut input1 = String::new();
let mut input2 = String::new();

println!("Enter number: ");
n = input1.trim().parse().expect("Not a valid number");

println!("Enter power: ");
p = input2.trim().parse().expect("Not a valid number");

res = n.pow(p);

println!("Result is: {}",res);
}
```

Output:

```RUN 1:
Enter number:
2
Enter power:
3
Result is: 8

RUN 2:
Enter number:
10
Enter power:
3
Result is: 1000

RUN 3:
Enter number:
7
Enter power:
5
Result is: 16807
```

Explanation:

Here, we read the number and power from the user. Then we calculated the power of a given number using the pow() function and printed the result.