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Rust program to calculate the power of a given number

Input the number (n) and power (p), find the power of the given number i.e., n to the power p (n^p) using Rust program.
Submitted by Nidhi, on September 26, 2021

Problem Solution:

Here, we will read the number and power from the user. Then we will calculate the power of a given number using the pow() function and print the result.

Program/Source Code:

The source code to calculate the power of a given number is given below. The given program is compiled and executed successfully.

// Rust program to calculate the 
// power of given number

use std::io;

fn main() {
    let mut n:u32 = 0;
    let mut p:u32 = 0;
    let mut res:u32 = 0;
    
    let mut input1 = String::new();
    let mut input2 = String::new();
    
    println!("Enter number: ");
    io::stdin().read_line(&mut input1).expect("Not a valid string");
    n = input1.trim().parse().expect("Not a valid number");

    println!("Enter power: ");
    io::stdin().read_line(&mut input2).expect("Not a valid string");
    p = input2.trim().parse().expect("Not a valid number");

    res = n.pow(p);
    
    println!("Result is: {}",res);
}

Output:

RUN 1:
Enter number: 
2
Enter power: 
3
Result is: 8

RUN 2:
Enter number: 
10
Enter power: 
3
Result is: 1000

RUN 3:
Enter number: 
7
Enter power: 
5
Result is: 16807

Explanation:

Here, we read the number and power from the user. Then we calculated the power of a given number using the pow() function and printed the result.

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