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Rust program to find the remainder without using the modulus (%) operator

Given two numbers, we have to find the remainder without using the modulus (%) operator using Rust program.
Submitted by Nidhi, on September 28, 2021

Problem Solution:

Here, we will read two integer numbers from the user and find the remainder without using the modulus (%) operator.

Program/Source Code:

The source code to find the remainder without using the modulus (%) operator is given below. The given program is compiled and executed successfully.

// Rust program to find the remainder 
// without using '%' operator

use std::io;

fn main() {
    let mut n1:i32 = 0;
    let mut n2:i32 = 0;
    let mut rem:i32 = 0;
    
    let mut input1 = String::new();
    let mut input2 = String::new();
    
    println!("Enter number1: ");
    io::stdin().read_line(&mut input1).expect("Not a valid string");
    n1 = input1.trim().parse().expect("Not a valid number");

    println!("Enter number2: ");
    io::stdin().read_line(&mut input2).expect("Not a valid string");
    n2 = input2.trim().parse().expect("Not a valid number");

	rem=n1-(n1/n2)*n2;
 
	println!("Remainder is: {}",rem);    
}

Output:

RUN 1:
Enter number1: 
66
Enter number2: 
3
Remainder is: 0

RUN 2:
Enter number1: 
9
Enter number2: 
5
Remainder is: 4

Explanation:

Here, we read the value of n1, n2 from the user. Then we found the remainder without using the modulus '%' operator. After that, we printed the result.

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