# Rust program to count the total number of HIGH (1) bits a given binary number

Here, we are going to learn how to count the total number of HIGH (1) bits a given binary number in Rust programming language?
Submitted by Nidhi, on September 24, 2021

Problem Solution:

Here, we will create a 16-bit integer number and then we will count the total HIGH (1) bits of the given number.

Program/Source Code:

The source code to count the total number of bits are HIGH (1) in a given binary number is given below. The given program is compiled and executed successfully.

```// Rust program to count total number of bits
// are HIGH (1) in a given binary number

fn main() {
let mut num:i16 = 14;
let mut val:i16 = 15;
let mut tmp:i16 = 0;
let mut cnt:i16 = 0;

println!("Decimal Number: {}",num);
print!("Binary Number: ");

while val>=0
{
tmp = num & (1<<val);
if tmp>0
{
print!("1");
cnt = cnt + 1;
}
else
{
print!("0");
}
val = val - 1;
}
println!("\nTotal HIGH bits are: {}",cnt);
}
```

Output:

```Decimal Number: 14
Binary Number: 0000000000001110
Total HIGH bits are: 3
```

Explanation:

Here, we created a 16-bit integer variable num with an initial value of 14. Then we counted the total HIGH (1) bits of a given number using bitwise operators and printed the result.