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Rust program to count the total number of HIGH (1) bits a given binary number

Here, we are going to learn how to count the total number of HIGH (1) bits a given binary number in Rust programming language?
Submitted by Nidhi, on September 24, 2021

Problem Solution:

Here, we will create a 16-bit integer number and then we will count the total HIGH (1) bits of the given number.

Program/Source Code:

The source code to count the total number of bits are HIGH (1) in a given binary number is given below. The given program is compiled and executed successfully.

// Rust program to count total number of bits 
// are HIGH (1) in a given binary number

fn main() {
    let mut num:i16 = 14;
    let mut val:i16 = 15;
    let mut tmp:i16 = 0;
    let mut cnt:i16 = 0;
    
    println!("Decimal Number: {}",num);
    print!("Binary Number: ");
	
    while val>=0
    {
        tmp = num & (1<<val);
        if tmp>0
        {
            print!("1");
            cnt = cnt + 1;
        }
        else
        {
            print!("0");
        }
        val = val - 1;
    }
    println!("\nTotal HIGH bits are: {}",cnt);
}

Output:

Decimal Number: 14
Binary Number: 0000000000001110
Total HIGH bits are: 3

Explanation:

Here, we created a 16-bit integer variable num with an initial value of 14. Then we counted the total HIGH (1) bits of a given number using bitwise operators and printed the result.

Rust Basic Programs »



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