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Rust program to swap nibbles of a number

Here, we are going to learn how to swap nibbles of a number in Rust programming language?
Submitted by Nidhi, on September 24, 2021

Problem Solution:

Here, we will create an 8-bit integer number and then we will swap the nibbles of the given number and print the result.

Program/Source Code:

The source code to swap nibbles of a number is given below. The given program is compiled and executed successfully.

// Rust program to swap nibbles of a number.

fn main()
{
    let mut num:u8 = 0x34;

    println!("Number before swapping nibbles is: {:#02x}", num);
    
    num = (num & 0x0F) << 4 | (num & 0xF0) >> 4;
    
    println!("Number after swapping nibbles is: {:#02x}", num);
}

Output:

Number before swapping nibbles is: 0x34
Number after swapping nibbles is: 0x43

Explanation:

Here, we created an 8-bit integer variable num with an initial value of 0x34. Then we swapped the nibbles of the given number and printed the result.

Rust Basic Programs »



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