Home » C/C++ Data Structure programs

# C program to implement Bubble Sort

**Bubble Sort Algorithm**: Here, we are going to learn about the bubble sort algorithm, how it works, and C language implementation of the bubble sort.

Submitted by Sneha Dujaniya, on June 19, 2020

**Bubble Sort** is a simple, stable, and in-place sorting algorithm.

- A
**stable sorting algorithm**is the one where two keys having equal values appear in the same order in the sorted output array as it is present in the input unsorted array. - An
**in-place sorting algorithm**has various definitions but a more used one is – An in-place sorting algorithm does not need extra space and uses the constant memory for manipulation of the input in-place. Although, it may require some extra constant space allowed for variables.

Due to its simplicity, it is widely used as a sorting algorithm by computer programmers.

The basic working principle of **bubble sort** is that it repeatedly swaps the adjacent elements if they are in the wrong order. Hence, after every full iteration, the largest element reaches its position as in the sorted array.

**Pseudo-code:**

1. for i: 0 to n-1 not inclusive do: 2. for j: 0 to n-i-1 not inclusive do: 3. If a[j] > a[j+1] then 4. swap a[j] and a[j+1] 5. end if 6. end for 7. end for

**Example:**

**Input Array: **

5 8 1 2 9

Here, I will run from **0 to 3**

Since, i < n-1 => i < 5-1 => i < 4

**Iteration 1 (i = 0):**

For j = 0, (**5 8** 1 2 9) -> (**5 8** 1 2 9) No swap because 5 < 8

For j = 1, (5 **8 1 **2 9) -> (5 **1 8** 2 9), swap because 1 < 8

For j = 2, (5 1 **8 2 **9) -> (5 1 **2 8 **9), swap because 2 < 8

For j = 3, (5 1 2 **8 9**) -> (5 1 2** 8 9**), no swap

1^{st} Pass gives – 5 1 2 8 9

**Iteration 2 (i = 1):**

For j = 0, (**5 1** 2 8 9) -> (**1 5** 2 8 9) No swap because 1 < 5

For j = 1, (1** 5** **2** 8 9) -> (1** 2 5** 8 9), swap because 2 < 5

For j = 2, (1 2** 5** **8** 9) -> (1 2** 5** **8** 9), no swap

2^{nd} Pass gives – 1 2 5 8 9

**Iteration 3 (i = 2):**

For j = 0, (**1 2** 5 8 9) -> (**1 2** 5 8 9), No swap because 1 < 2

For j = 1, (1** 2** **5** 8 9) -> (1** 2** **5** 8 9), No swap 2 < 5

3^{rd} Pass gives – 1 2 5 8 9

**Iteration 4 (i = 3):**

For j = 0, (**1 2** 5 8 9) -> (**1 2** 5 8 9), No swap because 1 < 2

4^{th} Pass gives – 1 2 5 8 9 because, last element is automatically sorted.

**Time Complexity: ** The time complexity of Binary Search can be described as: T(n) = T(n/2) + C

- Worst case: O(n^2)
- Average Case: O(n^2)
- Best case: O(n^2), since the loops run even if the array is sorted
- Space Complexity: O(1)

This simple **implementation of Bubble Sort** is just to explain the concept of the algorithm. In real life, whenever bubble sort is used, the optimized version is preferred over this one. That is because the optimized version gives **O(n)** time complexity in the best case.

In the optimized bubble sort, the inner loop doesn't run if the array is already sorted. Whereas, in the simple implementation, no such provision is there.

**Bubble Sort Implementation:**

#include <stdio.h> void swap(int* x, int* y) { int temp = *x; *x = *y; *y = temp; } void bubble_sort(int arr[], int n) { int i, j; for (i = 0; i < n - 1; i++) for (j = 0; j < n - i - 1; j++) if (arr[j] > arr[j + 1]) swap(&arr[j], &arr[j + 1]); } int main() { int arr[] = { 12, 46, 34, 82, 10, 9, 28 }; int n = sizeof(arr) / sizeof(arr[0]); printf("\nInput Array: \n"); for (int i = 0; i < n; i++) printf("%d ", arr[i]); bubble_sort(arr, n); printf("\nSorted Array: \n"); for (int i = 0; i < n; i++) printf("%d ", arr[i]); return 0; }

**Output:**

Input Array: 12 46 34 82 10 9 28 Sorted Array: 9 10 12 28 34 46 82

TOP Interview Coding Problems/Challenges

- Run-length encoding (find/print frequency of letters in a string)
- Sort an array of 0's, 1's and 2's in linear time complexity
- Checking Anagrams (check whether two string is anagrams or not)
- Relative sorting algorithm
- Finding subarray with given sum
- Find the level in a binary tree with given sum K
- Check whether a Binary Tree is BST (Binary Search Tree) or not
- 1[0]1 Pattern Count
- Capitalize first and last letter of each word in a line
- Print vertical sum of a binary tree
- Print Boundary Sum of a Binary Tree
- Reverse a single linked list
- Greedy Strategy to solve major algorithm problems
- Job sequencing problem
- Root to leaf Path Sum
- Exit Point in a Matrix
- Find length of loop in a linked list
- Toppers of Class
- Print All Nodes that don't have Sibling
- Transform to Sum Tree
- Shortest Source to Destination Path

Comments and Discussions