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Java program to find perimeter of a rectangle

In this java program, we are going to find perimeter of a rectangle, to find perimeter we need to take length and width as an input.
Submitted by IncludeHelp, on December 30, 2017

Given length and width of a rectangle and we have to find its perimeter using java program.

Formula to find perimeter of a rectangle: perimeter = 2 (Length + Width)


    Length: 25
    Width: 22

    Perimeter = 2 (25+22) = 94

Program to find perimeter of rectangle in java

import java.io.BufferedReader;
import java.io.IOException;
import java.io.InputStreamReader;

public class CalPerimeterOfRectangle 
	public static void main(String[] args)
		int width = 0;
		int length = 0;
			// create object of the buffer class.
			BufferedReader br = new BufferedReader(new InputStreamReader(System.in));

			// enter length and width of the rectangle.
			System.out.print("Enter length of the rectangle : ");
			length = Integer.parseInt(br.readLine());

			System.out.print("Enter width of the rectangle : ");
			width = Integer.parseInt(br.readLine());       
		// check for invalid value.
		catch(NumberFormatException ne)
			System.out.print("Invalid value" + ne);
		catch(IOException ioe)
			System.out.println("IO Error :" + ioe);
		// formula to calculate parimeter.
		int perimeter = 2 * (length + width);
		System.out.print("Perimeter of a rectangle is : " + perimeter);


Enter length of the rectangle : 25
Enter width of the rectangle : 22
Perimeter of a rectangle is : 94

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