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Java program to sort an array in ascending order

In this java program, we are going to learn how to read an integer array and sort array in ascending order? By IncludeHelp Last updated : December 23, 2023

Problem statement

Given an array of integers and print array in ascending order using java program.

Example

Input:  
12, 25, 99, 66, 33, 8, 9, 54, 47, 36

Output: 
8, 9, 12, 25, 33, 36, 47, 54, 66, 99

Sorting an array in ascending order

In this java program, we are reading total number of elements (N) first, and then according the user input (value of N)/total number of elements, we are reading the elements. Then sorting elements of array in ascending order and then printing the elements which are sorted in ascending order.

Java program to sort an array in ascending order

import java.util.Scanner;

public class ExArraySortElement {
  public static void main(String[] args) {
    int n, temp;
    //scanner class object creation
    Scanner s = new Scanner(System.in);

    //input total number of elements to be read
    System.out.print("Enter the elements you want : ");
    n = s.nextInt();

    //integer array object
    int a[] = new int[n];

    //read elements 
    System.out.println("Enter all the elements:");
    for (int i = 0; i < n; i++) {
      a[i] = s.nextInt();
    }

    //sorting elements
    for (int i = 0; i < n; i++) {
      for (int j = i + 1; j < n; j++) {
        if (a[i] > a[j]) {
          temp = a[i];
          a[i] = a[j];
          a[j] = temp;
        }
      }
    }

    //print sorted elements 		
    System.out.println("Ascending Order:");
    for (int i = 0; i < n; i++) {
      System.out.println(a[i]);
    }
  }
}

Output

Enter the elements you want : 10
Enter all the elements:
12
25
99
66
33
8
9
54
47
36
Ascending Order:
8
9
12
25
33
36
47
54
66
99

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