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Rust program to demonstrate the conditional operator

Here, we are going to demonstrate the conditional operator in Rust programming language.
Submitted by Nidhi, on September 22, 2021

Problem Solution:

Here, we will demonstrate the conditional/ternary operator to find out the number is EVEN or ODD.

Program/Source Code:

The source code to demonstrate the conditional operator is given below. The given program is compiled and executed successfully.

// Rust program to demonstrate 
// the conditional operator

fn main() {
    let mut num:i32=22;  
    if (num%2==0) { println!("EVEN") } else { println!("EVEN") }
}

Output:

EVEN

Explanation:

Here, we created an integer variable num initialized with 22. Then we used the ternary operator to find out the number is EVEN or ODD and printed the appropriate message.

Rust Basic Programs »



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