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Java program to demonstrate the getName() method

Java example to demonstrate the getName() method.
Submitted by Nidhi, on May 04, 2022

Problem Solution:

In this program, we will get the name of declared types using the getName() method and print the result.

Program/Source Code:

The source code to demonstrate the getName() method is given below. The given program is compiled and executed successfully.

// Java program to demonstrate the 
// getName() method

@interface A {}
public class Main {
  public static void main(String[] args) throws ClassNotFoundException {
    Class cls1 = A.class;
    Class cls2 = Main.class;

    System.out.println("The class name associated with cls1: " + cls1.getName());
    System.out.println("The class name associated with cls2: " + cls2.getName());
  }
}

Output:

The class name associated with cls1: A
The class name associated with cls2: Main

Explanation:

In the above program, we created a public class Main that contains a main() method. The main() method is the entry point for the program. Here, we got the name of interface A and class Main using the getName() method and printed the result.

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