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Java program to demonstrate the getName() method
Java example to demonstrate the getName() method.
Submitted by Nidhi, on May 04, 2022
Problem Solution:
In this program, we will get the name of declared types using the getName() method and print the result.
Program/Source Code:
The source code to demonstrate the getName() method is given below. The given program is compiled and executed successfully.
// Java program to demonstrate the
// getName() method
@interface A {}
public class Main {
public static void main(String[] args) throws ClassNotFoundException {
Class cls1 = A.class;
Class cls2 = Main.class;
System.out.println("The class name associated with cls1: " + cls1.getName());
System.out.println("The class name associated with cls2: " + cls2.getName());
}
}
Output:
The class name associated with cls1: A
The class name associated with cls2: Main
Explanation:
In the above program, we created a public class Main that contains a main() method. The main() method is the entry point for the program. Here, we got the name of interface A and class Main using the getName() method and printed the result.
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