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Java program to demonstrate the protected access specifier

Write a Java program to demonstrate the example protected access specifier.
Submitted by Nidhi, on March 24, 2022

Problem Solution:

In this program, we will 4 classes A, B, C, and Main. Classes A, B, C contains a method with a protected specifier. Here, we will implement multi-level inheritance in A, B, C classes.

The protected member of a class can be accessed:

  1. Within the same class.
  2. Derived classes of same packages.
  3. Different classes of the same packages.
  4. Derived classes of different packages.

Program/Source Code:

The source code to demonstrate the protected access specifier is given below. The given program is compiled and executed successfully.

// Java program to demonstrate the 
// protected access specifier

class A {
  protected void MethodA() {
    System.out.println("MethodA called");
  }
}

class B extends A {
  protected void MethodB() {
    System.out.println("MethodB called");
  }
}

class C extends B {
  protected void MethodC() {
    System.out.println("MethodC called");
  }
}

public class Main {
  public static void main(String[] args) {
    C obj = new C();

    obj.MethodA();
    obj.MethodB();
    obj.MethodC();
  }
}

Output:

MethodA called
MethodB called
MethodC called

Explanation:

In the above program, we created 4 classes A, B, C, and Main(). Here, we implemented multi-level inheritance and created methods using protected access specifiers.

The Main class contains a method main(). The main() method is the entry point for the program, here we created the object of class C and called methods of all inherited classes, and printed the messages.

Java Inheritance Programs »


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