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Kotlin program to sort an array in ascending order

Kotlin | Sorting an array (Ascending Order): Here, we are going to learn how to sort an array in ascending order in Kotlin programming language?
Submitted by IncludeHelp, on May 03, 2020

Given an array, we have to sort its elements in ascending order.

Example:

    Input:
    arr = [10, 20, 5, 2, 30]

    Output:
    sorted array (Ascending Order): [2, 5, 10, 20, 30]

Program to sort an array in ascending order in Kotlin

package com.includehelp.basic

import java.util.*

//Main Function entry Point of Program
fun main(args: Array<String>) {
    //Input Stream
    val s = Scanner(System.`in`)

    //Input Array Size
    print("Enter number of elements in the array: ")
    val size = s.nextInt()

    //Create Integer array of Given size
    val intArray = IntArray(size)

    //Input array elements
    println("Enter Arrays Elements:")
    for (i in intArray.indices) {
        print("intArray[$i] : ")
        intArray[i] = s.nextInt()
    }

    //to Perform Ascending Order Sorting on integer Array
    var temp:Int
    for (i in intArray.indices) {
        for (j in i + 1 until intArray.size) {
            if (intArray[i] > intArray[j]) {
                temp = intArray[i]
                intArray[i] = intArray[j]
                intArray[j] = temp
            }
        }
    }

    //Alternatively we can also use sort() method of Arrays 
    //Class in kotlin to sort in Ascending Order
    //intArray.sort()

    print("Ascending Order: ")
    for (item in intArray) {
        print("$item ")
    }
}

Output

Enter number of elements in the array: 6
Enter Arrays Elements:
intArray[0] : 5
intArray[1] : 23
intArray[2] : 1
intArray[3] : 0
intArray[4] : 9
intArray[5] : 76
Ascending Order: 0 1 5 9 23 76
----------------
Enter number of elements in the array: 8
Enter Arrays Elements:
intArray[0] : 45
intArray[1] : 3
intArray[2] : 89
intArray[3] : -8
intArray[4] : -45
intArray[5] : 0
intArray[6] : 432
intArray[7] : 6
Ascending Order: -45 -8 0 3 6 45 89 432