Home »
C programming language

# How expression a==b==c (Multiple Comparison) evaluates in C programming?

Since C language does not support chaining comparison like a==b==c; each equal to operator (==) operates on two operands only. Then how expression a==b==c evaluates?

According to operators associativity equal to operator (==) operates from left to right, that means associativity of equal operator (==) is left to right.

Expression a==b==c is actually (a==b) ==c, see how expression (a==b) ==c evaluates?

- (a==b) will be compared first and return either 1 (true) or 0 (false).
- Then value of variable c will be compared with the result of (a==b).

**Consider the following program**

#include <stdio.h>
int main(){
int a,b,c;
a=b=c=100;
if(a==b==c)
printf("True...\n");
else
printf("False...\n");
return 0;
}

Output

False...

### How output is "False..."?

See the program, the values of a, b and c is 100 and you are thinking **how condition is false here** and **why output is ****"False..."**?

The expression is a==b==c which will evaluates like (a==b)==c now **what will be the result?**

- The result of (a==b) is 1 (i.e. true).
- And (1)==c will be 0 (i.e. false) because the value of c is 100 and
**100 is equal not to 1**.

We are using Google to publish ads on our website; Google has its own privacy policies. They may save log, cookies on your system. Google may also collect information of your system like IP address, region, city, country. For more details please go through the Google’s privacy policy.