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Golang program to sort a slice of 64-bit floating-point numbers in ascending order

Here, we are going to learn how to sort a slice of 64-bit floating-point numbers in ascending order in Golang (Go Language)?
Submitted by Nidhi, on March 16, 2021 [Last updated : March 04, 2023]

Sorting a slice of 64-bit floating-point numbers in ascending order in Golang

Problem Solution:

In this program, we will create a slice and then sort slice elements using the sort.Float64s() function and then print sorted slice on the console screen.

Program/Source Code:

The source code to sort a slice of 64-bit floating-point numbers in ascending order is given below. The given program is compiled and executed successfully.

Golang code to sort a slice of 64-bit floating-point numbers in ascending order

// Golang program to sort a slice of 64-bit floating-point
// numbers in ascending order

package main

import "fmt"
import "sort"

func main() {
	slice := []float64{70.1, 20.2, 30.3, 60.4, 50.7, 60.8, 10.9}

	sort.Float64s(slice)

	fmt.Println("Sorted slice: ")
	for _, ele := range slice {
		fmt.Printf("%f ", ele)
	}
}

Output:

Sorted slice:
10.900000 20.200000 30.300000 50.700000 60.400000 60.800000 70.100000

Explanation:

In the above program, we declare the package main. The main package is used to tell the Go language compiler that the package must be compiled and produced the executable file. Here, we imported the fmt package that includes the files of package fmt then we can use a function related to the fmt package.

In the above program, we also imported the sort package to use the Float64s() function to sort 64-bit float slice.

In the main() function, we created a slice of 64-bit float numbers, then we sorted elements of the slice using the Float64s() function of the sort package. After that, we printed the result on the console screen.

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