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Linux shell script program to print program name using command line argument

Here, we are going to learn how to print program name using command line argument in Linux shell script?
Submitted by Nidhi, on February 14, 2021

Problem statement

Here, we will create a shell script program to print program name using the $0 variable on the console screen.

Print program name using command line argument

The source code to create a Linux shell script program to print program name using command-line argument is given below. The given program is compiled and executed successfully on Ubuntu 20.04.

Linux shell script program to print program name using command line argument

#!/bin/bash
# Program name: "script_name.sh"
# shell script program to print program name using command line argument.
echo "Script program Name: $0"

Now, we will save the shell script program with the "script_name.sh" name.

Output

$ sh script_name.sh 
Script program Name: script_name.sh

Explanation

Here, we used the $0 variable to print the program name on the console screen.

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