Learn: How to implement function overloading based on different number of argument in C++ programming language?

We can implement function overloading on the basis of number of arguments passed into function. Function overloading can be implementing in non-member function as well as member function of class.

Example of non-member function based function overloading according to number of arguments is given below:

```#include <iostream>
using namespace std;

void sum(int A, int B);
void sum(int A, int B, int C);
void sum(int A, int B, int C, int D);

int main()
{
sum(1,2);
sum(1,2,3);
sum(1,2,3,4);

return 0;
}

void sum(int A, int B)
{
cout<< endl << "SUM is : "<< A+B;
}

void sum(int A, int B, int C)
{
cout<< endl << "SUM is : "<< A+B+C;
}

void sum(int A, int B, int C, int D)
{
cout<< endl << "SUM is : "<< A+B+C+D;
}
```

Output

```SUM is : 3
SUM is : 6
SUM is : 10
```

Example of member function of class based function overloading according to number of arguments is given below:

```#include <iostream>
using namespace std;

class funOver
{
public:
void sum(int A, int B);
void sum(int A, int B, int C);
void sum(int A, int B, int C, int D);
};

void funOver::sum(int A, int B)
{
cout<< endl << "SUM is : "<< A+B;
}

void funOver::sum(int A, int B, int C)
{
cout<< endl << "SUM is : "<< A+B+C;
}

void funOver::sum(int A, int B, int C, int D)
{
cout<< endl << "SUM is : "<< A+B+C+D;
}

int main()
{
funOver ob;

ob.sum(1,2);
ob.sum(1,2,3);
ob.sum(1,2,3,4);

return 0;
}
```

Output

```SUM is : 3
SUM is : 6
SUM is : 10
```

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