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# Java program to check whether all bits of the number are UNSET (LOW)

Given/input an integer number, we have to check whether all bits of the number are UNSET (LOW).
Submitted by Nidhi, on March 06, 2022

## Problem statement

In this program, we will read a number from the user and check all bits of input number are UNSET/LOW.

## Java program to check whether all bits of the number are UNSET (LOW)

The source code to check whether all bits of the number are UNSET/LOW is given below. The given program is compiled and executed successfully.

```// Java program to check whether all bits
// of the number are UNSET/LOW

import java.util.Scanner;

public class Main {
static boolean isAllBitsUnset(byte num) {
int loop, cnt = 0;

for (loop = 7; loop >= 0; loop--) {
//check, if there is any SET/HIGH bit
if ((num & (1 << loop)) != 0) {
cnt = 1;
break;
}
}
if (cnt == 0)
return true;
else
return false;
}

public static void main(String[] args) {
Scanner SC = new Scanner(System.in);
byte number;

System.out.printf("Enter an integer number (between 0-255): ");
number = SC.nextByte();

if (isAllBitsUnset(number))
System.out.printf("All bits are UNSET/LOW.\n");
else
System.out.printf("All bits are not UNSET/LOW.\n");
}
}
```

### Output

```Enter an integer number (between 0-255): 4
All bits are not UNSET/LOW.
```

## Explanation

In the above program, we imported the "java.util.Scanner" package to read input from the user. And, created a public class Main. It contain two static methods isAllBitsUnset() and main().

The isAllBitsUnset() method is used to check all bits of a specified number are LOW or not and return a Boolean value to the calling method.

The main() method is an entry point for the program. Here, we read a number from the user using Scanner class and called isAllBitsUnset() method to check all bits of an input number is LOW or not and printed appropriate message.