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Java program to count the number of leading zeros in a binary number

Given/input a number, we have to count the number of leading zeros in a binary number.
Submitted by Nidhi, on March 11, 2022

Problem Solution:

In this program, we will read an integer number from the user. Then we will print its binary representation and count the leading 0s in binary representation.

Program/Source Code:

The source code to count the number of leading zeros in a binary number is given below. The given program is compiled and executed successfully.

// Java program to count the number of 
// leading zeros in a binary number

import java.util.Scanner;

public class Main {
  public static void main(String[] args) {
    Scanner SC = new Scanner(System.in);

    int num = 0;
    int cnt = 31;

    System.out.printf("Enter Number: ");
    num = SC.nextInt();

    System.out.printf("Binary number: ");
    while (cnt >= 0) {
      if ((num & (1 << cnt)) != 0)
        System.out.printf("1");
      else
        System.out.printf("0");

      cnt--;
    }

    cnt = 0;

    while ((num & (1 << 31)) == 0) {
      num = (num << 1);
      cnt++;
    }
    System.out.printf("\nNumber of leading zero's are: %d\n", cnt);
  }
}

Output:

Enter Number: 8
Binary number: 00000000000000000000000000001000
Number of leading zero's are: 28

Explanation:

In the above program, we imported the java.util.Scanner package to read the variable's value from the user. And, created a public class Main. It contains a static method main().

The main() method is an entry point for the program. Here, we read an integer number from the user. Then we printed its binary representation and count the leading 0's in the binary number. After that, we printed the number of leading 0's.

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