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Java program to count total HIGH bits of the given number

Given/input an integer number, we have to count total HIGH bits of the given number.
Submitted by Nidhi, on March 07, 2022

Problem Solution:

In this program, we will read a short integer from the user and find the total HIGH bits in the input number.

Program/Source Code:

The source code to count the total HIGH bits of the given number is given below. The given program is compiled and executed successfully.

// Java program to count total HIGH bits 
// of the given number

import java.util.Scanner;

public class Main {
  static int countHighBits(short num) {
    byte i;
    int count = 0;

    for (i = 0; i < 16; i++) {
      if ((num & (1 << i)) != 0)
        count++;
    }

    return count;
  }

  public static void main(String[] args) {
    Scanner SC = new Scanner(System.in);

    short num = 0;

    System.out.printf("Enter number: ");
    num = SC.nextShort();

    System.out.printf("\nTotal HIGH bits are : %d\n", countHighBits(num));
  }
}

Output:

Enter number: 7

Total HIGH bits are : 3

Explanation:

In the above program, we imported the "java.util.Scanner" package to read input from the user. And, created a public class Main. It contain two static methods countHighBits() and main().

The countHighBits() method is used to count the total HIGH bits of a given short integer using bitwise operators and return the result to the calling method.

The main() method is an entry point for the program. Here, we read a short integer number from the user using the Scanner class. Then we called the countHighBits() method and got the total number of HIGH bits and printed the result.

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