PHP program to demonstrate the call by value parameter passing

Here, we are going to demonstrate the call by value parameter passing in PHP.
Submitted by Nidhi, on November 19, 2020 [Last updated : March 13, 2023]

Call By Value Parameter Passing Example

Here, we will pass parameters using call by value mechanism to the user-defined function. In the call by value parameter passing, the updated value of parameters does not reflect in the calling function.

Example of call by value parameter passing in PHP

The source code to demonstrate the call by value parameter passing is given below. The given program is compiled and executed successfully.

<?php
//php program to demonstrate call by 
//value parameter passing.
function Sum($num1, $num2, $num3)
{
    $num3 = $num1 + $num2;

    echo "Inside function->num3: " . $num3 . "<br>";
}

$num1 = 10;
$num2 = 20;
$num3 = 0;

Sum($num1, $num2, $num3);
echo "Outside function->num3: " . $num3;
?>

Output

Inside function->num3: 30
Outside function->num3: 0

Explanation

In the above program, we created a function Sum() that accepts three arguments $num1, $num2, and $num3.

In the Sum() function, we calculated the addition of $num1 and $num2 and assigned the result to the $num3. Here, we printed the value of $num3 inside the function, it will print the sum of $num1 and $num2 on the webpage.

After that we created three variables $num1, $num2, and $num3 that are initialized with 10,20, and 30 respectively. Then we called Sum() method and printed the value of $num3, and it will print 0 because here we passed the parameters as call by value mechanism. And we know that in the call by value parameter passing, the updated value of parameters does not reflect in the calling function.

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