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Scala program to check a given number is exist in a sequence or not

Here, we are going to learn how to check a given number is exist in a sequence or not in Scala programming language?
Submitted by Nidhi, on June 03, 2021

Problem Solution:

Here, we will create a sequence of integer numbers using Seq collection class. Then we will check a sequence contains a specified number or not using contains() method and print the appropriate message on the console screen.

The Seq is a trait. It is used to represent the indexed sequence. It is immutable. It also maintains the insertion order of elements.

Program/Source Code:

The source code to check a given number exists in a sequence or not is given below. The given program is compiled and executed on the ubuntu 18.04 operating system successfully.

// Scala program to check a given number is 
// exist in a sequence or not

import scala.collection.immutable._

object Sample {
  // Main method
  def main(args: Array[String]) {
    var nums: Seq[Int] = Seq(10, 20, 30, 45, 56, 67, 78);
    var num: Int = 0;

    printf("Enter number: ");
    num = scala.io.StdIn.readInt();

    if (nums.contains(num))
      println(num + " exists in nums sequence.");
    else
      println(num + " does not exist in nums sequence.");

  }
}

Output:

Enter number: 45
45 exists in nums sequence.

Explanation:

Here, we used an object-oriented approach to create the program. And, we imported Collection classes using below statement,

import scala.collection.immutable._

Here, we also created a singleton object Sample and defined the main() function. The main() function is the entry point for the program.

In the main() function, we created a sequence nums using Seq collection. Then we read an integer number from the user and then we checked given number is exists in created sequence or not and print the appropriate message on the console screen.

Scala Sequence Programs »


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