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Java program to check if all the bits of a given integer number are HIGH or not

Given an integer number, we have to whether all the bits of the number are HIGH or not.
Submitted by Nidhi, on March 10, 2022

Problem Solution:

In this program, we will read an integer number from the user. Then we will check all bits of the given number are HIGH or not.

Program/Source Code:

The source code to check if all the bits of a given integer number are HIGH or not is given below. The given program is compiled and executed successfully.

// Java program to check if all the bits of a 
// given integer number are HIGH or not

import java.util.Scanner;

public class Main {
  public static void main(String[] args) {
    Scanner SC = new Scanner(System.in);

    int num = 0;
    int temp = 0;

    System.out.printf("Enter number: ");
    num = SC.nextInt();

    while (num > 0) {
      temp = num & 1;
      if (temp == 0) {
        System.out.printf("All bits are not set.");
        return;
      }
      num = num >> 1;
    }
    System.out.printf("All bits are set in its binary representation.");
  }
}

Output:

Enter number: 7
All bits are set in its binary representation.

Explanation:

In the above program, we imported the "java.util.Scanner" package to read the variable's value from the user. And, created a public class Main. It contains a static method main().

The main() method is an entry point for the program. Here, we read an integer number from the user using the Scanner class and checked all bits of a given number are HIGH in its binary representation.

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