# Java program to count the total HIGH bits in the given number

Given an integer number, we have to count the total HIGH bits in the number.
Submitted by Nidhi, on March 10, 2022

Problem Solution:

In this program, we will read an integer number from the user. Then we will count total HIGH bits in the given number.

Program/Source Code:

The source code to count the total HIGH bits in a given number is given below. The given program is compiled and executed successfully.

```// Java program to count the total HIGH bits
// in the given number

import java.util.Scanner;

public class Main {
public static void main(String[] args) {
Scanner SC = new Scanner(System.in);

int num = 0;
int cnt = 0;

System.out.printf("Enter number: ");
num = SC.nextInt();

while (num != 0) {
if ((num & 1) == 1) {
cnt++;
}
num = num >> 1;
}
System.out.printf("Number of HIGH bits are: %d\n", cnt);
}
}
```

Output:

```Enter number: 7
All bits are set in its binary representation.
```

Explanation:

In the above program, we imported the "java.util.Scanner" package to read the variable's value from the user. And, created a public class Main. It contains a static method main().

The main() method is an entry point for the program. Here, we read an integer number from the user using the Scanner class and count the total number of HIGH bits of input number and print the result.

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