Replace all vowels in a string using C++ STL function

In this article, we are going to see how to use C++ STL function find_first_of() to replace all the vowels by some other character?
Submitted by Radib Kar, on July 18, 2020

Prerequisite: C++ std::find_first_of()

Problem Statement:

Replace all the vowels by '*' using C++ STL function.




Of course, we can do it simply by checking each character of the input string. But to elaborate the usage of find_first_of() function.

So the algorithm is our collection of characters would be the vowels.

Let's say that vowels="aeiou" out of which we need to search. So each time we find any character out of those vowels we mark that as '*'. When we will not find any more we will be done.

Just for the example,

Input = "includehelp"
So firstly it finds 'i' and replaces with '*'
So input is now "*ncludehelp"
In next iteration it finds u and marks it with '*'
So input is now "*ncl*dehelp"
So on lastly we get
"*ncl*d*h*lp" and processing this step 
it returns std::npos and thus it stops.
#include <bits/stdc++.h>
using namespace std;

int main()
    string str;
    cout << "Input the string\n";
    cin >> str;

    cout << "After replacing all the vowels from the input string\n";

    string vowels = "aeiou";

    //while there is vowel in the string
    while (str.find_first_of(vowels) != string::npos) {
        //replaced the vowel with '*'
        str[str.find_first_of(vowels)] = '*'; 

    cout << "The updated string is: " << str << endl;

    return 0;


Input the string
After replacing all the vowels from the input string
The updated string is: *ncl*d*h*lp

The above procedure is computationally expensive that the naïve process where we can run a loop and replace vowels. But the purpose of the program is to show how we can use function find_first_of() efficiently to solve string searching problems.

Also if instead of vowels, we had to search for a long collection of characters it helps.



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