Home »
C#.Net
List<T>.Reverse() method with example in C#
C# List<T>.Reverse() method: Here, we are going to learn about the Reverse() method of List with example.
Submitted by IncludeHelp, on March 15, 2019
C# List<T>.Reverse() Method
List<T>.Reverse() method is used to reverse the all list elements.
Syntax:
void List<T>.Reverse();
Parameter: It accepts nothing.
Return value: It returns nothing – it's returns type is void
Example:
int list declaration:
List<int> a = new List<int>();
adding elements:
a.Add(10);
a.Add(20);
a.Add(30);
a.Add(40);
a.Add(50);
reversing elements:
a.Reverse();
Output:
50 40 30 20 10
C# Example to reverse list elements using List<T>.Reverse() Method
using System;
using System.Text;
using System.Collections.Generic;
namespace Test
{
class Program
{
static void printList(List<int> lst)
{
//printing elements
foreach (int item in lst)
{
Console.Write(item + " ");
}
Console.WriteLine();
}
static void Main(string[] args)
{
//integer list
List<int> a = new List<int>();
//adding elements
a.Add(10);
a.Add(20);
a.Add(30);
a.Add(40);
a.Add(50);
if (a.Count > 0)
{
//print the list
Console.WriteLine("list elements...");
printList(a);
}
else
{
Console.WriteLine("list is empty");
}
//reverse list elements
a.Reverse();
//list after reversing the elements
if (a.Count > 0)
{
Console.WriteLine("list elements after reversing elements...");
printList(a);
}
else
{
Console.WriteLine("list is empty");
}
//hit ENTER to exit
Console.ReadLine();
}
}
}
Output
list elements...
10 20 30 40 50
list elements after reversing elements...
50 40 30 20 10