Golang program to demonstrate the ParseDuration() function

Here, we are going to demonstrate the ParseDuration() function in Golang (Go Language).
Submitted by Nidhi, on March 21, 2021 [Last updated : March 04, 2023]

ParseDuration() function in Golang

Problem Solution:

In this program, we will use ParseDuration() function to create a time object based on a specified string. After that, we will print Minutes, Seconds, and Nanoseconds() based on the time value of time objects on the console screen.

Program/Source Code:

The source code to demonstrate the ParseDuration() function is given below. The given program is compiled and executed successfully.

Golang code to demonstrate the example of ParseDuration() function

// Golang program to demonstrate the
// ParseDuration() function

package main

import "fmt"
import "time"

func main() {
	time1, _ := time.ParseDuration("20h")
	time2, _ := time.ParseDuration("2h15m17s")
	time3, _ := time.ParseDuration("10µs")

	fmt.Printf("Total Minutes in time1: %f\n", time1.Minutes())
	fmt.Printf("Total Seconds in time2: %f\n", time2.Seconds())
	fmt.Printf("Total Nanoseconds in time3: %d\n", time3.Nanoseconds())
}

Output:

Total Minutes in time1: 1200.000000
Total Seconds in time2: 8117.000000
Total Nanoseconds in time3: 10000

Explanation:

In the above program, we declare the package main. The main package is used to tell the Go language compiler that the package must be compiled and produced the executable file. Here, we imported the fmt package that includes the files of package fmt then we can use a function related to the fmt package.

In the main() function, we created three-time objects using ParseDuration() function by specifying time value. After that, we printed Minutes, Seconds, Nanoseconds values corresponding to time objects on the console screen.

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