Golang program to find a specified string pattern within a byte array using regular expression

Here, we are going to learn how to find a specified string pattern within a byte array using regular expression in Golang (Go Language)?
Submitted by Nidhi, on April 16, 2021 [Last updated : March 04, 2023]

Finding a specified string pattern within a byte array using regular expression in Golang

Problem Solution:

In this program, we will find a specified pattern within a specified byte array using the Match() function. After that, print the appropriate message on the console screen.

Program/Source Code:

The source code to find a specified string pattern within a byte array using regular expression is given below. The given program is compiled and executed on the ubuntu 18.04 operating system successfully.

Golang code to find a specified string pattern within a byte array using regular expression

// Golang program to find a specified string pattern
// within a byte array using regular expression.

package main

import "fmt"
import "regexp"

func main() {
	result, _ := regexp.Compile("L([A-Z]+)N")

	bArray := []byte{'L', 'A', 'N'}
	if result.Match(bArray) {
		fmt.Println("Matched")
	} else {
		fmt.Println("Not Matched")
	}
}

Output:

Matched

Explanation:

In the above program, we declare the package main. The main package is used to tell the Go language compiler that the package must be compiled and produced the executable file. Here, we imported the fmt, regexp packages then we can use a function related to the fmt and regexp package.

In the main() function, we found a specified string pattern within the specified string using the Match() function and then print the appropriate message on the console screen.

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