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Golang program to find the given number is Armstrong or not using for loop

Here, we are going to learn how to find the given number is Armstrong or not using for loop in Golang (Go Language)?
Submitted by Nidhi, on March 06, 2021

Problem Solution:

In this program, we will read an integer number and check number is Armstrong or not, and print an appropriate message on the console screen.

Program/Source Code:

The source code to find the given number is Armstrong or not using the for loop is given below. The given program is compiled and executed successfully.

// GoLang program to find the given number is Armstrong or not
// using "for" loop.

package main

import "fmt"

func main() {
	var num int = 0
	var rem int = 0
	var res int = 0
	var tmp int = 0

	fmt.Print("Enter Number: ")
	fmt.Scanf("%d", &num)

	tmp = num
	for num > 0 {
		rem = num % 10
		res = res + (rem * rem * rem)
		num = num / 10

	}

	if tmp == res {
		fmt.Printf("Number is armstrong")
	} else {
		fmt.Printf("Number is not armstrong")
	}
}

Output:

RUN 1:
Enter Number: 153
Number is armstrong

RUN 2:
Enter Number: 123
Number is not armstrong 

Explanation:

In the above program, we declare the package main. The main package is used to tell the Go language compiler that the package must be compiled and produced the executable file. Here, we imported the fmt package that includes the files of package fmt then we can use a function related to the fmt package.

In the main() function, we created four variables num, rem, res, tmp that are initialized with 0. Then we read an integer number from the user and checked the given number is Armstrong or not. After that, we printed the appropriate message on the console screen.

Golang Looping Programs »



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