# C program to check a given character is a digit or not without using the library function

Here, we are going to learn how to check a given character is a digit or not without using the library function in C programming language?
Submitted by Nidhi, on July 16, 2021

Problem Solution:

Given a character, we have to check whether the given character is a digit or not without using the library function.

Program:

The source code to check a given character is a digit or not without using the library function is given below. The given program is compiled and executed using GCC compile on UBUNTU 18.04 OS successfully.

```// C program to check a given character is a digit or not
// without using library function

#include <stdio.h>

int isDigit(char ch)
{
if (ch >= '0' && ch <= '9')
return 1;

return 0;
}

int main()
{
char ch = 0;

printf("Enter character: ");
scanf("%c", &ch);

if (isDigit(ch))
printf("Given character is a digit\n");
else
printf("Given character is not a digit\n");

return 0;
}
```

Output:

```RUN 1:
Enter character: 8
Given character is a digit

RUN 2:
Enter character: 0
Given character is a digit

RUN 3:
Enter character: H
Given character is not a digit
```

Explanation:

In the above program, we created two functions isDigit() and main(). The isDigit() function is used to check the given character is a digit or not.

In the main() function, we read a character from the user and check given character is a digit or not by calling the isDigit() function and print the appropriate message on the console screen.

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