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C program to find the LCM (Lowest Common Multiple) of two integers

Here, we are going to learn how to find the LCM (Lowest Common Multiple) of two integers using C program?
Submitted by Nidhi, on August 03, 2021

Problem Solution:

Read two integer numbers, and find the (LCM) Lowest Common Multiple of given numbers.

Program:

The source code to find the LCM (Lowest Common Multiple) of two integers is given below. The given program is compiled and executed using GCC compile on UBUNTU 18.04 OS successfully.

// C program to find the LCM
// (Lowest Common Multiple) of two integers

#include <stdio.h>

int main()
{
    int num1 = 0;
    int num2 = 0;
    int rem = 0;
    int lcm = 0;
    int X = 0;
    int Y = 0;

    printf("Enter Number1: ");
    scanf("%d", &num1);

    printf("Enter Number2: ");
    scanf("%d", &num2);

    if (num1 > num2) {
        X = num1;
        Y = num2;
    }
    else {
        X = num2;
        Y = num1;
    }

    rem = X % Y;

    while (rem != 0) {
        X = Y;
        Y = rem;
        rem = X % Y;
    }

    lcm = num1 * num2 / Y;
    printf("Lowest Common Multiple is: %d\n", lcm);

    return 0;
}

Output:

RUN 1:
Enter Number1: 10
Enter Number2: 20
Lowest Common Multiple is: 20

RUN 2:
Enter Number1: 10
Enter Number2: 225
Lowest Common Multiple is: 450

RUN 3:
Enter Number1: 110
Enter Number2: 17
Lowest Common Multiple is: 1870

Explanation:

Here, we read two integer numbers num1 and num2 from the user and found the Lowest Common Multiple of both numbers, and printed the result on the console screen.

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