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C program to find the total of non-repeated elements of an array

Here, we are going to learn how to find the total of non-repeated elements of an array in C programming language?
Submitted by Nidhi, on July 11, 2021

Problem Solution:

Here, we will create an array of integers then find non-repeated elements from the array and count them.

Program:

The source code to find the total of non-repeated elements of an array is given below. The given program is compiled and executed using GCC compile on UBUNTU 18.04 OS successfully.

// C program to find the total of
// non-repeated elements of an array

#include <stdio.h>
#include <stdlib.h>

int main()
{
    int arr[] = { 1, 2, 3, 2, 2, 5, 6, 1 };

    int iLoop = 0;
    int jLoop = 0;
    int cnt = 0;

    for (iLoop = 0; iLoop < 8; iLoop++) {
        for (jLoop = 0; jLoop < 8; jLoop++) {
            if (arr[iLoop] == arr[jLoop] && iLoop != jLoop)
                break;
        }
        if (jLoop == 8) {
            cnt = cnt + 1;
        }
    }
    printf("Total non-repeated elements are: %d\n", cnt);

    return 0;
}

Output:

Total non-repeated elements are: 3

Explanation:

Here, we created an array arr with 8 elements. Then we iterated the array elements and find non-repeated elements from the array and count them. After that, we printed a count of non-repeated elements on the console screen.

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